Thm_ (By the axiom of choice)
Let S be a linear independent subset of a vector space V.
Then there exists a maximal linear independent subset β of V with S⊂β.
Proof_
Let F be the set of all linear independent subsets of V containing S.
Let C⊂F be any chain.
Define LC = ∪AA∈C. Then A⊂LC∀A∈C.
We check LC∈F. Since S⊂A∀A∈C, we have S⊂LC.
It remains to check that LC is linear independent.
Suppose u1,⋯,un∈LC,a1,⋯,an∈F. and a1u1+⋯+anun=0.
Then ∀i∈{1,⋯,n}, ui∈Ai for some Ai∈C.
Since C is a chain in F, ∃k∈{1,⋯,n} such that ui∈Ai⊂Ak∀i∈{1,⋯,n}.
Since Ak is linear independent, we have a1=⋯=an=0.
Thus, LC is linear independent, so that LC=F.
By Zorn's lemma, F has a maximal set, say β. This β is a desired set.
Coro_
Every vector space has a basis.
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